0 \\
0
\end{array}\right), \quad \mathbf{b}_{1}=\left(\begin{array}{c}
0 \\
27
\end{array}\right), \quad \mathbf{b}_{2}=\left(\begin{array}{l}
27 \\
27
\end{array}\right), \quad \mathbf{b}_{3}=\left(\begin{array}{c}
27 \\
0
\end{array}\right) Use the de Casteljau algorithm to determine the value x(3) as well as all intermediate points!
Fig: 1
Fig: 2
Fig: 3